Answer:
Gain of electron is reduction
and loss of electron is oxidation.
\[SnC{{l}_{2}}+HgC{{l}_{2}}\to
SnC{{l}_{4}}+Hg\]
\[S{{n}^{2+}}+H{{g}^{2+}}\to
S{{n}^{4+}}+Hg\]
\[S{{n}^{2+}}\to
S{{n}^{4+}}+2{{e}^{-}}\] (loss of electron, i.e., oxidation)
\[H{{g}^{2+}}+2{{e}^{-}}\to Hg\](gain
of electron, i.e., reduction)
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