• # question_answer 26) Why does the following reaction occur? $XeO_{6}^{4-}+2{{F}^{-}}(aq)+6{{H}^{+}}(aq)\to Xe{{O}_{3}}(g)+{{F}_{2}}(g)+3{{H}_{2}}O(l)$ What conclusion about the compound $N{{a}_{4}}Xe{{O}_{6}}$ (of which $XeO_{6}^{4-}$ is a part) can be drawn from the reaction?

${{F}^{-}}$ion is a very strong reducing agent and it reduces$XeO_{6}^{4-}$ to $Xe{{O}_{3}}$ (Xenon is reduced from +8 to +6 state). $N{{a}_{4}}Xe{{O}_{6}}$acts as an oxidising agent in this reaction.