Answer:
(i)\[\overset{+1}{\mathop{H}}\,-\overset{-2}{\mathop{O}}\,-\underset{\underset{\underset{-2}{\mathop{O}}\,}{\mathop{||}}\,}{\overset{\overset{\overset{-2}{\mathop{O}}\,}{\mathop{||}}\,}{\mathop{S}}}\,-\overset{-1}{\mathop{O}}\,-\overset{-1}{\mathop{O}}\,-\overset{+1}{\mathop{H}}\,\]
\[x+2-8=0\]
\[x=+6\]
Here, x is the oxidation state of sulphur.
(ii) \[\overset{-}{\mathop{O}}\,-\underset{\underset{O}{\mathop{||}}\,}{\overset{\overset{O}{\mathop{||}}\,}{\mathop{Cr}}}\,-O-\underset{\underset{O}{\mathop{||}}\,}{\overset{\overset{O}{\mathop{||}}\,}{\mathop{Cr}}}\,-\overset{-}{\mathop{O}}\,\]
Let x be the oxidation state of chromium.
\[\therefore \] \[2x-14=-2\]
\[x=+6\]
(iii)
Let oxidation state of nitrogen is
\[x-6=1\]
\[x=+5\]
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