question_answer 1)

  Calculate the oxidation number of each sulphur atom in the following compounds : (a) \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\]                          (b) \[N{{a}_{2}}{{S}_{4}}{{O}_{6}}\]                         (c)\[\text{N}{{\text{a}}_{\text{2}}}\text{S}{{\text{O}}_{\text{3}}}~~\]                   (d)\[\text{N}{{\text{a}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\]

Answer:

  (a) \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\] \[+2+2x-6=0\]                 \[x=+2\] (b) \[\overset{+}{\mathop{N}}\,a\overset{\overset{-2}{\mathop{-}}\,}{\mathop{O}}\,-\underset{\underset{\underset{-2}{\mathop{O}}\,}{\mathop{||}}\,}{\overset{\overset{\overset{-2}{\mathop{O}}\,}{\mathop{||}}\,}{\mathop{{{S}^{x}}}}}\,-\overset{0}{\mathop{S}}\,-\overset{0}{\mathop{S}}\,-\underset{\underset{\underset{-2}{\mathop{O}}\,}{\mathop{||}}\,}{\overset{\overset{\overset{-2}{\mathop{O}}\,}{\mathop{||}}\,}{\mathop{S}}}\,-\overset{(-2)}{\mathop{\overset{-}{\mathop{O}}\,N\overset{+}{\mathop{a}}\,}}\,\]                                 \[2x+2-12=0\]                                                 \[x=+5\] Two sulphur atoms are in (+5) and remaining two are in zero oxidation state.