Answer:
In \[Pb{{O}_{2}}\], lead is in
its max. oxidation state (+4) hence it will not react with oxidising agent \[HN{{O}_{3}}\].
However, \[PbO\]being basic oxide will form salt with\[HN{{O}_{3}}\].
\[\underset{Base}{\mathop{PbO}}\,+\underset{Acid}{\mathop{2HN{{O}_{3}}}}\,\to
\underset{Salt}{\mathop{Pb{{(N{{O}_{3}})}_{2}}}}\,+{{H}_{2}}O\]
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