question_answer 25)

What are hybridisation states of each carbon atom in the following compounds? (i) \[C{{H}_{2}}=C=O\] (ii) \[C{{H}_{3}}CH=C{{H}_{2}}\] (iii) \[{{(C{{H}_{3}})}_{2}}CO\] (iv)\[C{{H}_{2}}=CHCN\] (v) \[{{C}_{6}}{{H}_{6}}\]

Answer:

(i) \[\overset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,=\overset{sp}{\mathop{C}}\,=O\] (ii) \[\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\overset{s{{p}^{2}}}{\mathop{CH}}\,=\overset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,\] (iii) \[\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\underset{s{{p}^{2}}}{\overset{\overset{\text{O}}{\mathop{\text{ }\!\!|\!\!\text{ }\!\!|\!\!\text{ }}}\,}{\mathop{C}}}\,-\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,\] (iv)\[\overset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,=\overset{s{{p}^{2}}}{\mathop{CH}}\,-\overset{sp}{\mathop{C}}\,\equiv N\] (v) Each carbon in benzene \[({{C}_{6}}{{H}_{6}})\] is \[s{{p}^{2}}\] -hybridized.