question_answer 1)

  Electro negativity of carbon atoms depends upon their state of hybridisation. In which of the following compounds, the cabron marked with asterisk is most electronegative? (a) \[C{{H}_{3}}-C{{H}_{2}}-{{\,}^{*}}C{{H}_{2}}-C{{H}_{3}}\]                                        (b) \[C{{H}_{3}}-{{\,}^{*}}CH=CH-C{{H}_{3}}\] (c) \[C{{H}_{3}}-C{{H}_{2}}-C\equiv {{\,}^{*}}CH\]                                            (d) \[C{{H}_{3}}-C{{H}_{2}}-CH={{\,}^{*}}C{{H}_{2}}\]

Answer:

  (c) Electro negativity increases as the state of hybridization changes from\[s{{p}^{3}}-s{{p}^{2}}-sp\]. Thus, \[sp\]-carbon has the highest electro negativity.