Answer:
(i) \[PbS(s)+4{{H}_{2}}{{O}_{2}}(aq)\to
PbS{{O}_{4}}(s)+4{{H}_{2}}O(l)\]
In this reaction, \[{{H}_{2}}{{O}_{2}}\]
acts as an oxidising agent and provides oxygen to PbS as to convert it into\[PbS{{O}_{4}}\].
(ii) \[CO+3{{H}_{2}}\xrightarrow[Catayst]{Cobalt}C{{H}_{3}}OH\]
In this reaction, \[{{H}_{2}}\]
acts as a reducing agent.
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