Answer:
(b) \[{{H}_{2}}S{{O}_{4}}\underset{{}}{\leftrightarrows}{{H}^{+}}+HSO_{4}^{-}\]
Anode
\[HS{{O}_{4}}+{{e}^{-}}\]
\[2{{H}_{2}}{{S}_{2}}{{O}_{8}}+2{{H}_{2}}O\to
2{{H}_{2}}S{{O}_{4}}+{{H}_{2}}{{O}_{2}}\]
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