Answer:
\[2{{D}_{2}}+{{O}_{2}}\to
\underset{\begin{smallmatrix}
Heavy\,water \\
or
\\
Deuterium\,oxide
\end{smallmatrix}}{\mathop{2{{D}_{2}}O}}\,\]
Reactivity of deuterium will be
less than hydrogen as the bond dissociation energy of dideuterium is more than dihydrogen.
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