Answer:
In order to
prepare aIkane containing odd number of carbon atoms, a mixture of two different
aloalkanes are needed. Since, two haloalkanes can react in three different
ways, therefore, a mixture of three alkanes instead of the desired alkane would
be formed. For example, Wurtz reaction between bromoethane
and1-bromopropane gives a mixture of three alkanes, i.e., butane, pentane and
hexane as shown below:
\[\underset{Bromoethane}{\mathop{C{{H}_{3}}C{{H}_{2}}Br}}\,+2Na+\underset{Bromoethane}{\mathop{BrC{{H}_{2}}C{{H}_{3}}}}\,\xrightarrow[\Delta
]{Dry\,ether}\]\[\underset{\text{Butane}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}}}\,+2NaBr\]
\[\underset{Bromoethane}{\mathop{C{{H}_{3}}C{{H}_{2}}Br}}\,+2Na+B\underset{1-Bromopropane}{\mathop{rC{{H}_{2}}C{{H}_{2}}C{{H}_{3}}}}\,\xrightarrow[\Delta
]{Dry\,ether}\] \[\underset{\text{Pentane}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}}}\,+2NaBr\]
\[\underset{1-Bromopropane}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br}}\,+2Na+\underset{1-Bromopropane}{\mathop{BrC{{H}_{2}}C{{H}_{2}}C{{H}_{3}}}}\,\xrightarrow[\Delta
]{Dry\,ether}\]\[\underset{Hexane}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}}}\,+2NaBr\]
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