• # question_answer 15) How do you account for the formation of ethane during chlorination of methane?

Chlorination of methane proceeds by free radical mechanism. Initiation step: Propagation step: Termination step: $\underset{Methyl\,free\,radical}{\mathop{\overset{\centerdot }{\mathop{C}}\,{{H}_{3}}+\overset{\centerdot }{\mathop{C}}\,{{H}_{3}}}}\,\to \underset{Ethane}{\mathop{C{{H}_{3}}-C{{H}_{3}}}}\,$ Two $\overset{\centerdot }{\mathop{C}}\,{{H}_{3}}$ free radicals combine together to formethane molecule. $\overset{\centerdot }{\mathop{C}}\,{{H}_{3}}+\overset{\centerdot }{\mathop{Cl}}\,\to C{{H}_{3}}-Cl$ $\overset{\centerdot }{\mathop{Cl}}\,+\overset{\centerdot }{\mathop{Cl}}\,\to C{{l}_{2}}$