Answer:
(i) Due to
the presence of \[s{{p}^{3}}\] -hybridized carbon, the system is not planar. It
contains six \[\pi \]-electrons but the system is not fully conjugated since
all the six \[\pi \]-electrons do not form a single cyclic electron cloud.
Therefore, it is not an aromatic compound.
(ii) \[(4n+2)\]\[\pi \] -electron (Huckels rule) is not applicable.
It contains only four electrons and dueto the presence of a \[s{{p}^{3}}\]
-carbon, the system is not planar. Therefore, the system is not aromatic.
(iii) It is a non-planar system having eight \[\pi \]-electrons.
It does not contain a planar cyclic cloud having \[(4n+2)\]\[\pi \]-electrons.
Therefore, the molecule is not aromatic.
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