Answer:
Sodium
nitrite is the salt of weak acid and strong base.
\[pH=\frac{1}{2}[p{{K}_{w}}+p{{K}_{a}}+logC]\,\,\,\,\,\,\,\,\,\,\,......(i)\]
\[p{{K}_{w}}=14\]
\[p{{K}_{a}}=-{{\log }_{10}}{{K}_{a}}\]
\[=-\log [4.5\times {{10}^{-4}}]\]
\[=3.346\]
\[\log C=\log 0.04=-1.3979\]
Putting these values in Eqn. (i), we get
\[pH=\frac{1}{2}[14+3.346-1.3979]\]
\[=7.974\]
Degree
of hydrolysis,
\[h=\sqrt{\frac{{{K}_{w}}}{C{{K}_{a}}}}\]
\[=\sqrt{\frac{{{10}^{-14}}}{0.04\times
4.5\times {{10}^{-4}}}}\]
\[=2.357\times
{{10}^{-5}}\]
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