Answer:
\[\Delta {{n}_{g}}=3-2=1\]
\[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta
n}}\]
\[=3.75\times
{{10}^{-6}}{{(0.0821\times 1069)}^{1}}\]
\[=3.29\times
{{10}^{-4}}atm\]
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