Answer:
(b) \[C{{H}_{3}}COOH\]and\[N{{H}_{2}}OH\]are
weak acid and weak base.
\[{{K}_{b}}(C{{H}_{3}}COOH)={{K}_{b}}(N{{H}_{4}}OH)\]
Thus, \[C{{H}_{3}}COON{{H}_{4}}\]
will behave as buffer.
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