11th Class Chemistry Equilibrium / साम्यावस्था

  • question_answer 1)
      For the reaction: \[{{N}_{2}}(g)+3{{H}_{2}}(g)\underset{{}}{\leftrightarrows}2N{{H}_{3}}(g)\] Equilibrium constant \[{{K}_{c}}=\frac{{{[N{{H}_{3}}]}^{2}}}{[{{N}_{2}}]{{[{{H}_{2}}]}^{3}}}\] Some reactions are written below in Column I and their equilibrium constants in terms of \[{{K}_{c}}\] are written in Column II. Match the following reactions with the corresponding equilibrium constant.  
    Column l (Reaction) Column II (Equilibrium constant)
    (i) \[2{{N}_{2}}(g)+6{{H}_{2}}(g)\underset{{}}{\leftrightarrows}4N{{H}_{3}}(g)\] (a) \[2{{K}_{c}}\]
    (ii) \[2N{{H}_{3}}(g)\underset{{}}{\leftrightarrows}{{N}_{2}}(g)+3{{H}_{2}}(g)\] (b) \[K_{c}^{\frac{1}{2}}\]
    (iii) \[\frac{1}{2}{{N}_{2}}(g)+\frac{3}{2}{{H}_{2}}(g)\underset{{}}{\leftrightarrows}N{{H}_{3}}(g)\] (c) \[\frac{1}{{{K}_{c}}}\]
      (d) \[K_{c}^{2}\]
       
     

    Answer:

      (i-d) (ii-c) (iii-b)


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