Answer:
HCNO is a
weak acid it undergoes ionisation as follows:
\[\underset{\begin{smallmatrix}
t=0 \\
{{t}_{eq}}
\end{smallmatrix}}{\overset{{}}{\mathop{{}}}}\,\,\,\,\,\underset{\begin{smallmatrix}
C \\
C-C\alpha
\end{smallmatrix}}{\mathop{HCNO}}\,\rightleftharpoons
\underset{\begin{smallmatrix}
0 \\
C\alpha
\end{smallmatrix}}{\mathop{{{H}^{+}}}}\,+\underset{\begin{smallmatrix}
0 \\
C\alpha
\end{smallmatrix}}{\mathop{\overset{-}{\mathop{C}}\,NO}}\,\]
\[[{{H}^{+}}]=C\alpha \]
\[\therefore
\] \[C\alpha =\text{Antilog }\!\![\!\!\text{ -pH }\!\!]\!\!\text{ }\]
\[0.1\times
\alpha =\text{Antilog }\!\![\!\!\text{ -2}\text{.34 }\!\!]\!\!\text{ }\]
Degree of ionisation, \[\alpha \] = 0.0457
\[{{K}_{a}}=\frac{C\alpha
\times C\alpha }{1-\alpha }\]
\[=\frac{C{{\alpha
}^{2}}}{1-\alpha }=\frac{0.1\times {{(0.00457)}^{2}}}{1-0.0457}\]
\[=2.188\times
{{10}^{-4}}\]
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