question_answer 1)

Write down the expression for the equilibrium constant,\[{{K}_{c}}\] for each of the following reactions: (i) \[2NOCl(g)\rightleftharpoons 2NO(g)+C{{l}_{2}}(g)\] (ii) \[2Cu{{(N{{O}_{3}})}_{2}}(s)\rightleftharpoons 2CuO(s)+4N{{O}_{2}}(g)+{{O}_{2}}(g)\] (iii) \[C{{H}_{3}}COO{{C}_{2}}{{H}_{5}}(aq)+{{H}_{2}}O(aq)\rightleftharpoons C{{H}_{3}}COOH(aq)\] \[+{{C}_{2}}{{H}_{5}}OH(aq)\] (iv)\[F{{e}^{3+}}(aq)+3O{{H}^{-}}(aq)\rightleftharpoons Fe{{(OH)}_{2}}(s)\] (v) \[{{I}_{2}}(s)+5{{F}_{2}}(g)\rightleftharpoons 2I{{F}_{5}}(g)\]

Answer:

(i) \[{{K}_{c}}=\frac{{{[NO]}^{2}}[C{{l}_{2}}]}{{{[NOCl]}^{2}}}\] (ii) \[{{K}_{c}}={{[N{{O}_{2}}]}^{4}}[{{O}_{2}}]\] (iii) \[{{K}_{c}}=\frac{[C{{H}_{3}}COOH][{{C}_{2}}{{H}_{5}}OH]}{[C{{H}_{3}}COO{{C}_{2}}{{H}_{5}}][{{H}_{2}}O]}\] (iv)\[{{K}_{c}}=\frac{1}{[F{{e}^{3+}}]{{[OH]}^{3}}}\] (v) \[{{K}_{c}}=\frac{{{[I{{F}_{5}}]}^{2}}}{{{[{{F}_{2}}]}^{5}}}\]