Answer:
The electronic configuration of
outermost orbit in the alkali metals is \[n{{s}^{1}}\] where n = 2, 3, 4, 5, 6
and 7.
Li ; Na ; K ;
Rb ; Cs ; Fr
\[2{{s}^{1}}\] \[3{{s}^{1}}\]
\[4{{s}^{1}}\] \[5{{s}^{1}}\] \[6{{s}^{1}}\] \[7{{s}^{1}}\]
Because of their similarity in
electronic configuration [noble gas] \[n{{s}^{1}}\], they are placed in the
same group, i.e., IA of the periodic table. These elements are monovalent and closely
resemble in their physical and chemical properties.
You need to login to perform this action.
You will be redirected in
3 sec