11th Class Chemistry Chemical Bonding and Molecular Structure

  • question_answer 96)                 Matching the species in column I with the type of hybrid orbitals in column ll.  
    Column I Column II
    (i)\[S{{F}_{4}}\] (a) \[s{{p}^{3}}{{d}^{2}}\]
    (ii) \[I{{F}_{5}}\] (b) \[{{d}^{2}}s{{p}^{3}}\]
    (iii)\[NO_{2}^{+}\] (c) \[s{{p}^{3}}d\]
    (iv) \[NH_{4}^{+}\] (d) \[s{{p}^{3}}\]
      (e) \[sp\]
     

    Answer:

        (i?c) , (ii?a), (iii?e) , (iv?d) The type of hybrid orbitals can be evaluated by applying the following formula : \[H=\frac{1}{2}[V+M-C+A]\]                 \[S{{F}_{4}}=\frac{1}{2}[6+4-0+0]=5(s{{p}^{3}}d)\]                 \[I{{F}_{5}}=\frac{1}{2}[7+5-0+0]=6(s{{p}^{3}}{{d}^{2}})\]                 \[NO_{2}^{+}=\frac{1}{2}[5+0-1+0]=2(sp)\]                 \[NH_{4}^{+}=\frac{1}{2}[5+4-1+0]=4(s{{p}^{3}})\]                


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