JEE Main & Advanced Mathematics Trigonometrical Ratios and Identities Trigonometrical Ratios In Terms of Each Other

Trigonometrical Ratios In Terms of Each Other

Category : JEE Main & Advanced

 $\mathbf{sin}\,\mathbf{\theta }$ $\mathbf{cos}\,\mathbf{\theta }$ $\mathbf{tan}\,\mathbf{\theta }$ $\mathbf{cot}\,\,\mathbf{\theta }$ $\mathbf{sec}\,\,\mathbf{\theta }$ $\mathbf{cosec}\,\,\mathbf{\theta }$ $\mathbf{sin}\,\mathbf{\theta }$ $\sin \,\theta$ $\sqrt{1-{{\cos }^{2}}\theta }$ $\frac{\tan \theta }{\sqrt{1+{{\tan }^{2}}\theta }}$ $\frac{1}{\sqrt{1+{{\cot }^{2}}\theta }}$ $\frac{\sqrt{{{\sec }^{2}}\theta -1}}{\sec \theta }$ $\frac{1}{\text{cosec}\theta }$ $\mathbf{cos}\,\mathbf{\theta }$ $\sqrt{1-{{\sin }^{2}}\theta }$ $\cos \theta$ $\frac{1}{\sqrt{1+{{\tan }^{2}}\theta }}$ $\frac{\cot \theta }{\sqrt{1+{{\cot }^{2}}\theta }}$ $\frac{1}{\sec \theta }$ $\frac{\sqrt{\text{cose}{{\text{c}}^{2}}\theta -1}}{\text{cosec}\theta }$ $\mathbf{tan}\,\mathbf{\theta }$ $\frac{\sin \theta }{\sqrt{1-{{\sin }^{2}}\theta }}$ $\frac{\sqrt{1-{{\cos }^{2}}\theta }}{\cos \theta }$ $\tan \,\theta$ $\frac{1}{\cot \theta }$ $\sqrt{{{\sec }^{2}}\theta -1}$ $\frac{1}{\sqrt{\text{cose}{{\text{c}}^{2}}\theta -1}}$ $\mathbf{cot}\,\,\mathbf{\theta }$ $\frac{\sqrt{1-{{\sin }^{2}}\theta }}{\sin \theta }$ $\frac{\cos \theta }{\sqrt{1-{{\cos }^{2}}\theta }}$ $\frac{1}{\tan \theta }$ $\cot \,\theta$ $\frac{1}{\sqrt{{{\sec }^{2}}\theta -1}}$ $\sqrt{\text{cose}{{\text{c}}^{2}}\theta -1}$ $\mathbf{sec}\,\,\mathbf{\theta }$ $\frac{1}{\sqrt{1-{{\sin }^{2}}\theta }}$ $\frac{1}{\cos \theta }$ $\sqrt{1+{{\tan }^{2}}\theta }$ $\frac{\sqrt{1+{{\cot }^{2}}\theta }}{\cot \theta }$ $\sec \,\theta$ $\frac{\text{cosec}\theta }{\sqrt{\text{cose}{{\text{c}}^{2}}\theta -1}}$ $\mathbf{cosec}\,\,\mathbf{\theta }$ $\frac{1}{\sin \theta }$ $\frac{1}{\sqrt{1-{{\cos }^{2}}\theta }}$ $\frac{\sqrt{1+{{\tan }^{2}}\theta }}{\tan \theta }$ $\sqrt{1+{{\cot }^{2}}\theta }$ $\frac{\sec \theta }{\sqrt{{{\sec }^{2}}\theta -1}}$ $\text{cosec}\,\,\theta$

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