**Category : **JEE Main & Advanced

In every triangle the sum of the squares of any two sides is equal to twice the square on half the third side together with twice the square on the median that bisects the third side.

For any triangle *ABC*, \[{{b}^{2}}+{{c}^{2}}=2({{h}^{2}}+{{m}^{2}})=2\{{{m}^{2}}+{{(a/2)}^{2}}\}\] by use of cosine rule.

If \[\Delta \] be right angled, the mid point of hypotenuse is equidistant from the three vertices so that \[DA=DB=DC\].

\[\therefore {{b}^{2}}+{{c}^{2}}={{a}^{2}}\] which is pythagoras theorem. This theorem is very useful for solving problems of height and distance.

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